8085 Simple programming Examples

The programmes are based on the Data transfer group for other group search in our search box

Let’s do a program

MVI   A,20h

STA   5050h

HLT

Here, ‘MVI A, 20h’ stores the 20h in accumulator, and STA stores the content of accumulator to to 5050.

OUTPUT

A:20

           [5050]:20

                  

1)      Store accumulator content indirect

·         STAX Rp;

·         1 byte instruction

To understand this instruction let’s take an example

LXI            D,4060h;

MVI          A,20h;

STAX        D              ;[4060]ß20h

HLT

Here, LXI loads the immediate data 4060h to register pair D ,MVI moves 20h data to  accumulator and STAX instruction  content of accumulator is stored in address pointed by register D.

So he output is

D:40  E:60

A:20                                  

[4020]: 20

2)      Input from input port

Do yourself

3)      Output to output

Do yourself      

1)      write a program to move data from register B to C,C to D and D to E.

MOV        C,B   ; moves data from register B to C

MOV        D,C    ;moves data from register C to D

MOV        D,E     ; moves data from register ram D to E

HLT                     ;stops the program

Output :

Let register B contains data 20h

B: 20h   C: 20h

D: 20h   E:  20h

2)      Write a program to store 20h in address 4040.

1^st  method

LXI      H, 4030h      ; stores 4030h in HL register pair

MVI     B,20h          ; stores 20h to register B

MOV   M,B             ; moves content of register B to memory location 4040

HLT

2^Nd method

MVI   A, 20h

STA    4040h

HLT

Output

B: 20         C: J J

H:40            L:30

[4040] : 20

Write a program to store the data 40H and 20H to the address 5051 and 5052 respectively.

Method 1

LXI      H, 5051h     ; Loads 5051 to HL pair

MVI    M, 40h         ; moves the data 40 h to memory location pointed by HL i.e.5051

LXI      H, 5052h     ; Loads address location 5051 to HL pair

MOV   M,20h          ; moves the data 40 h to memory location pointed by HL ie,5051

HLT                         ; stops the program

Method 2

MVI   A, 40H      ; Moves data 40H to the accumulator

STA    5051H      ; Loads the content of accumulator content to address 5051

MVI    A, 20H     ; Moves data 20H Accumulator

STA    5052H      ; Loads the content of accumulator content to address 5052

HLT

Output

[5051] : 40

[5052] : 20

2) Write the program to store the data from the memory location 2051 and 2052 to register B and C respectively.

(Before doing this program in simulator load data in memory location 2051 and 2052 yourself)

Method 1

LDA     2051H      ; load the content of address 2051 to the accumulator

MOV   B,A           ; Moves the data from Acc.  Register to B

LDA    2052H       ; load the content of address 2051 to the accumulator

MOV   C,A           ; Moves the data from Acc. to register C

HLT

Method 2

LXI         H,2051H   ;loads 2051 to HL pair

MOV      B,M          ;moves the content of memory ( i.e. address containing  in HL pair ) to B reg